x^2-5=-10x

Solution for x^2-5=-10x equation:

x^2-5=-10x

We move all terms to the left:

x^2-5-(-10x)=0

We get rid of parentheses

x^2+10x-5=0

a = 1; b = 10; c = -5;
Δ = b2-4ac
Δ = 102-4·1·(-5)
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{30}}{2*1}=\frac{-10-2\sqrt{30}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{30}}{2*1}=\frac{-10+2\sqrt{30}}{2}
$